Very easy sumation (calculator allowed)

Algebra Level 4

If f(n)=1(n+(n+1))2n(n+1),f(n) = \frac{1}{(n + (n + 1))^2 - n(n + 1)},

then find 1f(1)+1f(2)+1f(3)+...+1f(99).\frac { 1 }{ f(1) } +\frac { 1 }{ f(2) } +\frac { 1 }{ f(3) } +...+\frac { 1 }{ f(99) }.

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