# Very very beautiful

Algebra Level 5

Consider the equation $(x+y)^2=(x+1)(y-1)$

If all the possible real ordered pairs $$(x,y)$$ that satisfy the equation above are $$(x_1,y_1),(x_2,y_2),...,(x_n,y_n)$$ then find the value of $$x^2_1+...+x^2_n+y^2_1+...+y^2_n$$.

• If you think there are infinite solutions then answer 777 and if you think no real solutions answer 666.
• Ordered pair means (11,12),(12,11) are considered different.

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