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100(a12+1)(a22+1)⋯(a102+1)100 (a_1^2 + 1)(a_2^2 + 1)\cdots (a_{10}^2 + 1) 100(a12+1)(a22+1)⋯(a102+1)
Let a1,a2,…,a10a_1, a_2, \ldots,a_{10} a1,a2,…,a10 denote the roots to the equation ∑m=110mxm=0 \displaystyle \sum_{m=1}^{10} m x^m = 0 m=1∑10mxm=0. Find the value of the expression above.
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