Forgot password? New user? Sign up
Existing user? Log in
∑n=119999n/20009n/2000+3\large \displaystyle\sum_{n=1}^{1999}\dfrac{9^{n/2000}}{9^{n/2000}+3}n=1∑19999n/2000+39n/2000
If the value of the summation above can be expressed as ab\dfrac abba, where aaa and bbb are coprime positive integers, find a+ba+ba+b.
Problem Loading...
Note Loading...
Set Loading...