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Algebra Level 5

r+19100+r+20100++r+91100=546.\left \lfloor r+\frac{19}{100} \right \rfloor+\left \lfloor r+\frac{20}{100} \right \rfloor+\cdots+\left \lfloor r+\frac{91}{100} \right \rfloor=546.

Given that rr is a real number that satisfy the equation above, find the value of 100r\lfloor 100r \rfloor.

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