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Algebra Level 5

$\left \lfloor r+\frac{19}{100} \right \rfloor+\left \lfloor r+\frac{20}{100} \right \rfloor+\cdots+\left \lfloor r+\frac{91}{100} \right \rfloor=546.$

Given that $$r$$ is a real number that satisfy the equation above, find the value of $$\lfloor 100r \rfloor$$.

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