Warm up problem 7: telescoping series easy-medium

Algebra Level 3

If the value of

13+115+135+...1483\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+...\frac{1}{483}

Can be expressed as ab\frac{a}{b} where a,b are positive co prime integers, find a+b.

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