\[\large {e}^{y}+y(x-2)=x^{2}-8\]

The equation above defines \(y\) implicitly as a function of \(x\) near the point \((3,0)\). Estimate the value of \(y\) when \(x=2.98\). Given the answer in 2 decimal places.

\(\)

**Clarification:** \(e \approx 2.71828\) denotes the Euler's number.

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