# Well, there is a lot of length bashing required!

Geometry Level 5

There is a trapezium $$ABCD$$ with parallel sides $$AB$$ and $$DC$$ and height 1. It is known that $$\angle DAB = 6^{\circ}$$ and $$\angle ABC = 42^{\circ}$$. Point $$P$$ is on side $$AB$$ such that $$\angle APD = 78^{\circ}$$ and $$\angle CPB = 66^{\circ}$$.

What is the value of $$AD-BC+DP-CP$$?

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