# Two Versus Three

$\begin{array} { l l l l l } & \color{red}{y} & +\frac { 1 }{ 2 } & +\frac { \color{red}{y} }{ 4 } & +\frac { 1 }{ 8 } & +\frac { \color{red}{y} }{ 16 } & +\frac { 1 }{ 32 }& + \dots\\ = & 1 & +\frac { \color{blue} {x} }{ 3 } & +\frac { 1 }{ 9 } & +\frac { \color{blue} {x} }{ 27 } & +\frac { 1 }{ 81 } & +\frac { \color{blue} {x} }{ 243 } & +\dots \end{array}$

Find the smallest positive integer $$\color{blue} {x}$$, such that there exists an integer $$\color{red}{y}$$ which satisfies the above equation.

×