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A=∑cycα3βγ+1\large \mathcal A =\displaystyle\sum_{\text{cyc}} \frac{\alpha^3}{\beta\gamma+1} A=cyc∑βγ+1α3
If α,β\alpha,\betaα,β and γ\gammaγ are roots of the equation x3−7x2+5x+2=0x^3-7x^2+5x+2=0x3−7x2+5x+2=0, then find A\mathcal AA.
Try the Part-1 and this problem first.
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