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If 2sinθ1+cosθ+sinθ=x\frac{2\sin\theta}{1+\cos\theta+\sin\theta}=x1+cosθ+sinθ2sinθ=x ,then 1−cosθ+sinθ1+sinθ=?\frac{1-\cos\theta+\sin\theta}{1+\sin\theta}=?1+sinθ1−cosθ+sinθ=?
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