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If a2b+c=b2c+a=c2a+b=1 \dfrac{a^2}{b+c} = \dfrac{b^2}{c+a}=\dfrac{c^2}{a+b}=1b+ca2=c+ab2=a+bc2=1, then find the value of 1a+1+1b+1+1c+1 \dfrac{1}{a+1} + \dfrac{1}{b+1} + \dfrac{1}{c+1} a+11+b+11+c+11
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If b+ca2=c+ab2=a+bc2=1, then find the value of
a+11+b+11+c+11
