Forgot password? New user? Sign up
Existing user? Log in
1+12+13+14+16+18+19+112+116+118+⋯= ?1+\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{1}{6}+\dfrac{1}{8}+\dfrac{1}{9}+\dfrac{1}{12}+\dfrac{1}{16}+\dfrac{1}{18}+\cdots = \, ?1+21+31+41+61+81+91+121+161+181+⋯=?
Clarification: The denominators are all positive integers whose prime divisors are either 2 and/or 3 only. In other words, they exclude all numbers with a prime factor greater than 3.
Problem Loading...
Note Loading...
Set Loading...