# What sort of sorcery is this?

Algebra Level 2

$\large{ \begin{cases} ab = a^b \\\\ \frac{a}{b} = a ^ {3b} \\ \end{cases}}$

$$a$$ and $$b$$ are real numbers, such that $$a > 1$$ and $$b \neq 0$$, satisfying the above system.

Find $$b ^ { -a}.$$

×