Where does the particle stop?

A charged particle enters a region where it experiences a drag force proportional to its velocity, that is, Fdrag=kv. \vec{F}_{drag}=- k \vec{v}. The initial velocity of the particle is v0v_{0}. Because of this force, the particle stops and the magnitude of its displacement is L0=10cmL_{0}=10 \textrm{cm}. The same experiment is repeated, this time a magnetic field BB (perpendicular to the particle's velocity) is applied. The particle spirals and comes to a stop. Now the the magnitude of its displacement is L1=6cm L_{1}=6 \textrm{cm}. What would be the particle's displacement L2L_{2} in meters if the magnetic field is reduced by a factor of 2? Note that in all three cases, the initial velocity of the particle is the same. Hint: This problem can be solved without calculus.

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