\(3\div4\times6\times(-2)\div3+(-4)\div(-7)\times14-(-3)\times\)

\((6-4\times(-2))\div(-7)-(-3)\times(-2)\div(-12)\times(-2)\times4\)

\(-5\times10\times2\div(-15)\times3-(-3)\times(3\times4-3\times4)\)

\(\div(-4)\times(-3)-(-1)-5\times6\div5\times6\ \)

Yes that is one complete arithmetic expression.

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