Albert walks with uniform acceleration in the North Direction. John, from the same starting position, walks left with uniform speed of \(10ms^{-1}\). Given that the shortest distance between them after 10 seconds is \(125m\), find Albert's speed at 5 seconds (\(ms^{-1}\))

*Details*
Precision of 5.39 is 0.39

\(pre(5.00)=0\)

\(pre(10.38738383)=38738383\)

They both started with initial speed of 0

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