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∫0∞x3e−3xsinx dx \large \int _{ 0 }^{ \infty } { x }^{ 3 }{ e }^{ -3x }\sin { x } \, dx ∫0∞x3e−3xsinxdx
If the integral above is the form of ab \dfrac abba, where aaa and bbb are coprime positive integers, find a+ba+ba+b.
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