Forgot password? New user? Sign up
Existing user? Log in
S=∑a=12015(∑b=12015(−1)a−12b)∑c=120151c \large{S = \dfrac{\displaystyle \sum^{2015}_{a=1} \left(\sum^{2015}_{b=1} \frac{(-1)^{a-1}}{2b} \right)}{\displaystyle \sum^{2015}_{c=1}\frac{1}{c}}}S=c=1∑2015c1a=1∑2015⎝⎛b=1∑20152b(−1)a−1⎠⎞
Evaluate the value of 4030S4030S4030S upto three correct places of decimals.
Inspiration.
Problem Loading...
Note Loading...
Set Loading...