Inspired by Calvin Lin - Why do I love 2015 so much 4

Algebra Level 5

\[\large{P= \left \lfloor \displaystyle \prod^{1008}_{n=1} \dfrac{2n}{2n-1} \right \rfloor}\]

Submit the value of \(36P\) as your answer.

This problem is a part of this set.
Akshat Sharda by Akshat Sharda
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