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1a4+1b4+1c4=1\dfrac{1}{a^4}+\dfrac{1}{b^4}+\dfrac{1}{c^4}=1a41+b41+c41=1
Given the above equation for positive numbers a,b,ca,b,ca,b,c.
Find the minimum value of
a4b4+a4c4+b4c4a3b2c3\dfrac{a^4b^4+a^4c^4+b^4c^4}{a^3b^2c^3}a3b2c3a4b4+a4c4+b4c4
If the minimum value of the above is xxx, input your answer as ⌊100x⌋\lfloor 100x \rfloor⌊100x⌋.
This is part of the set Trevor's Ten
Details and Assumptions
The answer is not 300300300.
It is indeed a3b2c3a^3 b^2 c^3a3b2c3 and not a3b3c3a^3 b^3 c^3 a3b3c3
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