# Winning on a Crooked Roll

Two six-sided dice each have the numbers 1 through 6 on their faces. Neither die is fair, but they are both weighted the same. The probability of rolling a certain number on one die is given in the table below:

$\begin{array}{c|cccccc} \mbox{number} & 1 & 2 & 3 & 4 & 5 & 6\\ \hline \mbox{probability} & \frac{1}{6} & \frac{1}{6} & \frac{1}{9} & ? & \frac{2}{9} & ?\\ \end{array}$

If the probability that the two dice both show the same numbers is $\left(\frac{2}{3}\right)^4$, we can express the probability of rolling 10 on these two dice as $\frac{a}{b}$ where $a$ and $b$ are coprime positive integers. What is the value of $a + b$?

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