# WMTC 2013 problem!

Geometry Level pending

in tetrahedron P-BCD, PB=PC=PD=BC= sqrt{3} . if angle BCD = 90 degrees, and length of CD is 1, find the tangent of the planar angle B-PD-C.

also i dont know how to use the LaTeX... :( also what is a planar angle, i found this question on an test, i know the answer but i did not know how to solve it

Moderator's edit:

In a tetrahedron $$PBCD$$, $$PB=PC=PD=BC = \sqrt3$$, if $$\angle BCD = 90^\circ$$, and the length of $$CD = 1$$, find the tangent of the planar angle $$\angle BPDC$$.

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