# Yay for 2014! #2

Algebra Level 4

Given that

$2014^{2} = 4056196$

find the sum of the digits of the exact value of

$(20142014.2014)^{2}$

Notes:

Exact value means that no rounding occurs while calculating, so the exact value of $$(2.1)^{2}$$ is $$4.41$$, not $$4.4$$ or $$4$$.

The sum of the digits of a number includes the digits of any decimal places, so the sum of the digits of $$4.41$$ would be $$4 + 4 + 1 = 9$$.

This problem is part of the set Yay for 2014!.

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