Given that

$2014^{2} = 4056196$

find the sum of the digits of the exact value of

$(20142014.2014)^{2}$

**Notes:**

Exact value means that no rounding occurs while calculating, so the exact value of $(2.1)^{2}$ is $4.41$, not $4.4$ or $4$.

The sum of the digits of a number includes the digits of any decimal places, so the sum of the digits of $4.41$ would be $4 + 4 + 1 = 9$.

This problem is part of the set Yay for 2014!.

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