Year 2016

Algebra Level 2

\[\dfrac{x{(x+5)}^{2016}{(x-3)}^{2017}{(6-x)}^{1231}}{{(x-2)}^{10000}{(x+1)}^{2015}{(4-x)}^{242}} \geq 0\]

Find all the possible values of \(x\).

Clarification: In the options, \(\cup \) stands for union.

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