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A=∑m=1∞∑n=1∞m2n4m(n4m+m4n) \large A = \displaystyle \sum_{m=1}^{\infty} \sum_{n=1}^{\infty} \dfrac{m^2n}{4^m (n4^m+m4^n)} A=m=1∑∞n=1∑∞4m(n4m+m4n)m2n
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