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True or False?
It's obvious that 0+0=0+0+00 + 0 = 0 + 0 + 0 0+0=0+0+0.
We can rewrite this equation as 2×0=3×02\times 0 = 3\times 0 2×0=3×0.
If a×b=c×da \times b = c\times d a×b=c×d is fulfilled, then a÷c=d÷b a\div c = d \div b a÷c=d÷b must be fulfilled too.
So 2÷3=0÷0 2\div 3 = 0 \div 0 2÷3=0÷0 must be correct.
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