# You don't have to find the $a'$s

Probability Level 5

$\large x_n=\sum_{k=0}^{9}a_k n^k$

For the given values of the numbers $a_k$ for $k=0,1,2,\cdots, 9,$ it is true that $x_n=e^n$ for $n=1, 2, \cdots, 10.$ Find $\left\lfloor x_{11}\right\rfloor.$

Clarification: $\displaystyle e = \lim_{n\to \infty} \left(1 +\dfrac1n \right)^n \approx 2.71828$.

×

Problem Loading...

Note Loading...

Set Loading...