You multiply by 9 by adding a 0

A three-digit number \(N\) (in decimal) contains the digit \(0\). When the zero is removed, the resulting number is exactly \(\frac{N}{9}\). What is the value of \(N\)?

Note: The number may contain more than one zero. The number may not begin with a zero.

×

Problem Loading...

Note Loading...

Set Loading...