# $$\zeta$$ $$\eta$$ day

Level pending

If the lag angle in a helicopter($$\zeta$$) is given to be 30, and Krish applied a force parallel to an inclined friction less plane where the inclination is just because of $$\zeta$$ with the horizontal, then $$\eta$$ of the helicopter's blade due to the Krish's force is?

Details : Angle measured in degrees. Use your mind what can be$$\eta$$ is?

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