Find sum of all even divisors of N
What is the sum of all the integers \(a\) such that the following equation has no real roots:
All the 7-digit numbers containing each of the digits 1, 2, 3, 4, 5, 6, 7 exactly once, and not
divisible by 5, are arranged in the increasing order. Find ...
√2 + √3 = 3.14 (approximately). Does this have any significance or is it just a coincidence?
Let n!=1x2x3x4x...xn for integer n>=1. If p =1!+(2+2!)+(3+3!)+...+(10+10!), then p+2 when divided by 11! leaves a remainder of?