Let's combine the terms in this equation. We have s and 3 s. Think of s as 1 s. So 1 s + 3 s gives us 4s.
The t term stays separate. This gives us 4 s + t = 20.
Let's try another. In the equation 3 C + S + 2 C = 25, we combine 3 C and 2 C.
Adding 3 + 2 gives us 5, so we have 5 C.
The S term stays by itself. The simplified equation is 5 C + S = 25.
This time we have three terms, 20 C, 5 C, and 2 C. We combine them by adding 20 + 5 + 2 = 27. That gives us 27 C. The A term stays by itself. The equation simplifies to A + 27 C = 4.
Here we combine terms on the right side.
We have 2 B and 4 B. Together they make 6B.
We also have four and 8.
Adding those gives us 12. So the right side simplifies to 6 b + 12.
This equation has two sets of terms.
First the a terms 5 a and 3 a. Adding them gives us 8 a. Next the b terms 2 b and 3 b. They combine to make 5b. Our rewritten equation is 8 a + 5 b = 20.
For this last problem, we'll combine terms on both sides separately. On the left side, we have 6 x and 2x. Adding those gives us 8 x. The two stays as it is. On the right side, we have y and 8 y. Remember that y is the same as 1 y.
So 1 y + 8 y = 9 y. The five remains.
Our simplified equation is 8x + 2 = 9 y + 5. We can identify terms with the same variable or constant terms without a variable and combine them.