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\[ \large \begin{cases} {a+b+c=7} \\ {a^2+b^2+c^2= 23} \\ {\frac1{a+b} +\frac1{b+c} + \frac1{a+c} = 31 } \end{cases} \]

If \(a,b\) and ...

IF it is given that a+b=c+d AND ab=cd, does it imply that a=c and b=d or a=d and b=c?

What is the output of the following VBScript?

i = 1

FOR a = 1 to 6

i = i * a

Next a

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