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\( f(p) = \begin{cases} \frac{ \sqrt p}{p^2} \text {if}, p = 4 \\ \frac{p^2}{\sqrt p} \text{if}, -2 \leq p < 4 \\ \sqrt[3]{p^2 + 2p}, \text{if}, 4<p \leq 6 \end{cases} \)

\[ \large \lim_{t \to 3} \frac{t^2 - 9 }{t - 3} = \ ?\ \]

\( \large \displaystyle \lim_{x \to - \infty} \frac{1}{x} = \ ?\ \)

This problem is part of this set

\( \large \displaystyle \lim_{x \to \infty} \frac{1}{x} = \ ?\ \)

\( \large \displaystyle \lim_{h \to 0} \frac{\sin{h}}{h} = \ ?\ \)

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