Arithmetic and Geometric Progressions Problem Solving

The average of the first 100 positive integers is $\text{\_\_\_\_\_\_\_\_\_\_}.$

If $A, B, C, D$ are consecutive terms in an arithmetic progression, what is the value of

$$\frac{ D^2 - A^2 } { C^2 - B^2} ?$$

Assume $C^2 - B^2 \neq 0.$

$$54+51+48+45+ \cdots$$

You are given the sum of an arithmetic progression of a finite number of terms, as shown above.

What is the minimum number of terms used to make a total value of 513?

One side of an equilateral triangle is 24 cm. The midpoints of its sides are joined to form another triangle whose midpoints, in turn, are joined to form still another triangle. This process continues indefinitely.

Find the sum of the perimeters of all these triangles that are defined above.

Once a man did a favor to a king that made the king very happy. Out of joy the king told the man to wish for anything and he would be granted. The man wanted to ask for the whole kingdom which was worth 1500 trillion dollars, but obviously that would make the king mad and he would never be granted that wish.

The man who happened to be a mathematician thought a little bit and said the following:

"Bring in a big piece of rug with an $8\times 8$ grid in it. Starting from the top left square, put one dollar in that square. Put two dollars in the square next to it and then double of that, four dollars, in the next square and so on. When you reach the end of the first row, continue on to the next row, doubling the amount every time as you move to the next square, all the way until the $64^\text{th}$ square at the bottom right."

The king thought for a second. The first square will take one dollar, the second two dollars, the third, four dollars, and next 8 dollars, and then 16 dollars, and then 32 dollars, 64 dollars, 128 dollars, 256 dollars, and so on. That's not too bad. I can do it.

The king agreed. What happened next?

$$1+2 \cdot 2+ 3 \cdot 2^2 + 4 \cdot 2^3 + \cdots+ 100 \cdot 2^{99}= \, ?$$

Real numbers $a_1,a_2,\ldots,a_{99}$ form an arithmetic progression.

Suppose that $$a_2+a_5+a_8+\cdots+a_{98}=205.$$ Find the value of $\displaystyle \sum_{k=1}^{99} a_k$.

The value of $\displaystyle \sum_{n=1}^ \infty \frac{ 2n}{ 3^n }$ can be expressed in the form $\frac{a}{b}$, where $a$ and $b$ are coprime positive integers. Find $a - b$.

Let $a,b,c$ be positive integers such that $\frac{b}{a}$ is an integer. If $a,b,c$ are in geometric progression and the arithmetic mean of $a,b,c$ is $b+2,$ find the value of

$$\dfrac{a^2+a-14}{a+1}.$$

If an infinite GP of real numbers has second term $x$ and sum $4,$ where does $x$ belong?

4 positive integers form an arithmetic progression.

If we subtract $2,6,7$ and $2,$ respectively, from the 4 numbers, it forms a geometric progression.

What is the sum of these 4 numbers?

Let $a, b \in R^{+}.$

$a, A_{1}, A_{2}, b$ is an arithmetic progression.
$a, G_{1}, G_{2}, b$ is a geometric progression.

Which of the following must be true?

We have three numbers in an arithmetic progression, and another three numbers in a geometric progression. Adding the corresponding terms of the two series, we get $120 , 116 , 130$. If the sum of all the terms in the geometric progression is $342$, what is the largest term in the geometric progression?

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Details and Assumptions:

• If the terms of the AP are A, B, C, and the terms of the GP are X, Y, Z, then adding the corresponding terms will give us A+X, B+Y, C+Z.

$$(1-x)(1-2x)(1-4x)\cdots \left(1-2^{101}x\right)$$

What is the coefficient of $x^{101}$ in the expansion of the above?

$$\frac {2+6}{4^{100}} + \frac {2+2 \times 6}{4^{99}} + \frac {2+ 3 \times 6}{4^{98}} + \cdots + \frac {2+ 100 \times 6}{4}$$

Evaluate the above expression.

In JEE examination the paper consists of 90 questions. The marks are awarded in such a way that if a person gets a question correct, he gets $+4$ marks; if he does it wrong, he gets $-2$ marks; if he leaves the question unanswered, he gets $0$ marks (as per 2015). Find the sum of all possible marks that a student can get in JEE.

Let $A=\{a_1, a_2, \ldots, a_n\}$ be a set of the first $n$ terms of an arithmetic progression. Similarly, let $B=\{b_1, b_2, \ldots, b_n\}$ be a set of the first $n$ terms of a geometric progression.

If a new set $C=A+B=\{a_1+b_1, a_2+b_2, \ldots, a_n+b_n\}$ and the first four terms of $C$ are $\{0, 0, 1, 0\},$ what is the $11^\text{th}$ term of $C?$

A linear function $f(x)=bx+a$ has the property that $f\big(f(x)\big)=dx+c$ is another linear function such that $a,b,c,d$ are integers that are consecutive terms in an arithmetic sequence. Find the last three digits of the sum of all possible values of $f(2013)$.

$$\begin{aligned} &\displaystyle\sum_{n=0}^{7}\log_{3}(x_{n}) &= 308 \\ 56 \leq & \log_{3}\left ( \sum_{n=0}^{7}x_{n}\right )& \leq 57 \\ \end{aligned}$$

The increasing geometric sequence $x_{0},x_{1},x_{2},\ldots$ consists entirely of integral powers of 3. If they satisfy the two conditions above, find $\log_{3}(x_{14}).$

Suppose $2015$ people of different heights are arranged in a straight line from shortest to tallest such that

(i) the tops of their heads are collinear, and

(ii) for any two successive people, the horizontal distance between them is equal to the height of the shorter of the two people.

If the shortest person is $49$ inches tall and the tallest is $81$ inches tall, then how tall is the person at the middle of the line, (in inches)?

Given that $a_1,a_2,a_3$ is an arithmetic progression in that order so that $a_1+a_2+a_3=15$ and $b_1,b_2,b_3$ is a geometric progression in that order so that $b_1b_2b_3=27$.

If $a_1+b_1, a_2+b_2, a_3+b_3$ are positive integers and form a geometric progression in that order, determine the maximum possible value of $a_3$.

The answer is of the form $\dfrac{a+b\sqrt{c}}{d}$, where $a$, $b$, $c$, and $d$ are positive integers and the fraction is in its simplest form and $c$ is square free. Submit the value of $a + b + c + d$.