Factoring Compound Quadratics:
A compound quadratic is a polynomial that can be expressed in the form , where and are constants, and is a positive integer. This can be generalized to compound polynomials, where the degree of the terms is a multiple of some positive integer.
Contents
Method
To solve a compound quadratic equation such as , one introduces a new variable . The equation becomes , and we can then solve for , after which we may solve for .
In general, it is possible to solve any compound polynomial equation , by considering it as a polynomial with the substitution , if one knows the solutions to .
Worked Examples
Often, an equation can look difficult to solve, but it can often be quite simple if you can see how to reduce it. A common example, a quartic of the form can be made much simpler by the substitution So the equation becomes a quadratic, which of course is much easier to solve.
For the solution, you can either factor it expicitly where and are the solutions (or roots) of the equation, or you can use the quadratic equation
Here are a few examples:
Solve the equation .
Substitute
Plugging into the quadratic equation,
This has two solutions: .
Finally, so has the four purely imaginary roots
Solve the equation .
First, we need to identify . Since the LHS is a polynomial in as well as , it seems suitable that we choose . We thus substitute , obtaining .
Factoring this equation, we get that ; hence, and thus .
As a result, we have .
Solve the equation .
Again, we need to identify . It seems is appropriate here, so we substitute , obtaining .
We multiply both sides by , and reject . We therefore get ; hence, and thus .
As a result, we have , with and . (To see how one arrives at the solution set, look up the roots of unity.)
If is real and positive, what is to 1 decimal place?