What is dxdxex?
Applying the product rule with u=x and v=ex, we get that
dxdxex=xdxdex+exdxdx=x×ex+ex×1=(x+1)ex.
Hence, dxdxex=(x+1)ex. □
Find the derivative of
f(x)=x2sinx.
Since (x2)′=2x and (sinx)′=cosx,
f′(x)=(2x)(sinx)+(cosx)(x2)=2xsinx+x2cosx. □
What is dxdcf(x)?
We may recognize this as a basic property of integerals. Applying the product rule with u=c and v=f(x), we get that
dxdcf(x)=cdxdf(x)+f(x)dxdc=cf′(x)+f(x)×0=cf′(x).
Hence, dxdcf(x)=cf′(x). □
Some functions may require the combined use of differentiation rules, such as this one here:
ex2(2xsin(ex)+cos(ex))
2xex2sin(ex)+ex2+xcos(ex)
2xexsin(ex)+ex2+xcos(ex)
2ex2sin(ex)+ex2cos(ex)
Find the derivative of
f(x)=ex2sin(ex).
The correct answer is:
2xex2sin(ex)+ex2+xcos(ex)
If you are having some trouble, you may want to review the chain rule.