# Probability - By Complement

The **complement** of an event is the subset of outcomes in the sample space that are not in the event. A complement is itself an event.

The complement of an event \(A\) is denoted as \(A^c\) or \(A'\). An event and its complement are mutually exclusive and **exhaustive**. This means that in any given experiment, either the event or its complement will happen, but not both. By consequence, the sum of the probabilities of an event and its complement is always equal to 1.

The study of complements is important because their properties allow for the efficient calculation of probabilities.

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## Interpreting Complements

When exploring probability problems, it is important to be able to describe complements and to recognize when an event can be interpreted as a complement.

An event and its complement are mutually exclusive. This means that the event and its complement do not share any outcomes. An event and its complement are also exhaustive. This means that the event and its complement together contain all outcomes in the sample space.

Let \(A\) and \(B\) be events in sample space \(S\).

\(A\) and \(B\) are

exhaustiveif \(A\cup B=S\).

When an event is described to you as something that could possibly happen, the complement of that event is *every other* possible thing that could happen.

There is a box with red, blue, and green balls. A ball is drawn at random from the box. Let \(R\) be the event that a red ball is drawn. Describe \(R^c\).

Since any ball you select will either be red, blue, or green, if the ball is not red, it will be either blue or green. \(R^c\) must be the event that you draw a green or blue ball.

It is perhaps more difficult to recognize when an event can be described as the complement of another event. Reinterpreting events as complements of other events is a useful skill which can aid in calculating probabilities efficiently.

A fair 6-sided die is rolled three times. Let \(A\) be the event that

at least oneof the rolls is a 6. Describe \(A\) as the complement of another event.

This problem is asking us to reinterpret \(A\) as the complement of another event. We need to think of what would happen if there

wasn'tat least one 6 among the three rolls.If there

wasn'tat least one 6 among the three rolls, then that means thatnoneof the rolls are 6.Let \(B\) be the event that none of the three rolls have a result of 6. Then \(B^c=A\).

This complement relationship between "none" events and "at least one" events is very important, and it shows up frequently in the study of probability.

Consider an experiment with multiple trials. Let \(x\) be an outcome of one of those trials.

If \(A\) is the event that \(x\) occurs

zero timesin the experiment, then \(A^c\) is the event that \(x\) occursat least oncein the experiment.

## Complement Rule

In a probability experiment, the probability of all possible events (the sample space) must total to 1— that is, some outcome must occur on every trial. For two events to be complements, they must be mutually exclusive and exhaustive, meaning that one or the other *must* occur. Therefore, the probabilities of an event and its complement must always total to 1.

For any given event \(A\):

\[P(A) + P(A^c) = 1\]

Equivalently, \(P(A^c) = 1- P(A)\).

Note: this does not, however, mean that any two events whose probabilities total to 1 are each other's complements; complementary events must also fulfil the condition of mutual exclusivity.

## Suppose a fair six-sided die is rolled 10 times. What is the probability that a 1 is rolled at least once?

Recall that "at least one" events can often be expressed as the complement of "none" events.

Let \(A\) be the event that a 1 is rolled

notimes in 10 rolls.As the 10 die rolls are mutually independent, we can calculate \(P(A)\) using the rule of product. Each die roll has a \(\dfrac{5}{6}\) probability of being a number other than 1. There are 10 rolls, and so

\(P(A)=\left(\dfrac{5}{6}\right)^{10} \approx 0.161506\)

\(A^c\) will be the event that a 1 is rolled

at least oncein 10 rolls.\(P(A^c)=1-P(A)\approx 0.838494\)

There is approximately a \(\boxed{0.838494}\) probability that there will be at least one roll of 1 among the 10 rolls.

IF \(A\) and \(B\) are two independent events such that \(P (A^c \cap B ) =\dfrac2{15} \), and \( P (A \cap B^c) = \dfrac16 \), find \(P(A) \) and \(P(B) \).

**Cite as:**Probability - By Complement.

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