Stewart's Theorem
In geometry, Stewart's theorem yields a relation between the side lengths and a cevian length of a triangle. It can be proved from the law of cosines as well as by the famous Pythagorean theorem. Its name is in honor of the Scottish mathematician Matthew Stewart who published the theorem in 1746 when he was believed to be a candidate to replace Colin Maclaurin as Professor of Mathematics at the University of Edinburgh.
Contents
Stewart's Theorem
In , point is a point on and Stewart's theorem states that in this triangle, the following equation holds:
Proof by the Law of Cosines
By the law of cosines, we have Now multiply (1) by and multiply (2) by to eliminate : Taking gives
Stewart's theorem can sometimes be rewritten as .
Proof by the Pythagorean Theorem
The proof below assumes and are both acute and as in the figure above. Then we have which implies
Special case where is Isosceles
In the case where is isosceles (see figure above), Stewart's theorem has a more simplified form: This theorem is quite useful in calculating the length of standard cevians like median, angle bisector, etc.
Additional Problems
In triangle , and .
If , then the value of can be expressed as , where and are positive integers and is square-free.
Find .
Triangle with its centroid at has side lengths . is the midpoint of .
The length of can be expressed as , where and are coprime positive integers and is a square-free positive integer.
Find .
In , , point is on such that , and is the midpoint of such that and .
If the area of is , where and are positive integers and is square-free, find .
Let be a square, and let and be points on and respectively. The line through parallel to and the line through parallel to divide into two squares and two non-square rectangles. The sum of the areas of the two squares is of the area of square
Find
A cyclic quadrilateral is constructed within a circle such that and is equilateral, as shown to the right.
If is the intersection point of both diagonals of , what is the length of the blue line segment in the diagram?