For a given closed surface , recall that Gauss' law holds that
where is the total charge enclosed within . If a distribution displays some symmetry (i.e., depends on in a simple way or not at all), then the surface integral need not be computed directly.
The standard examples for which Gauss' law is often applied are spherical conductors, parallel-plate capacitors, and coaxial cylinders, although there are many other neat and interesting charges configurations as well.
To compute the capacitance, first use Gauss' law to compute the electric field as a function of charge and position. Next, integrate to find the potential difference, and, lastly, apply the relationship .
The following examples illustrate the elementary use of Gauss' law to calculate the electric field of various symmetric charge configurations.
Charged hollow sphere. A charged hollow sphere of radius has uniform surface charge density . Determine the electric field due to the sphere.
Choose as a Gaussian surface a concentric sphere of radius . For , Gauss' law gives
For , no charge is enclosed in the Gaussian surface, so the field is also zero.
Infinite plane with charge. An infinite plane of charge has uniform surface charge density . Determine the electric field due to the plane.
Choose as a Gaussian surface a cylinder (or prism) whose faces are parallel to the sheet, each a distance from the sheet. By symmetry, the electric field must point perpendicular to the plane, so the electric flux through the sides of the cylinder must be zero. If the area of each face is , then Gauss' law gives
Note that is constant and independent of . This can be justified by considering the fact that the problem looks "identical" no matter how far one "zooms out"; an infinite plane is infinite. (And in fact, this argument is sufficient establish that is a constant.)
Charged cylinder. An hollow cylindrical rod of radius has uniform charge per unit length . Determine the electric field due to the rod.
We choose as our Gaussian surface a concentric cylinder of radius . Consider a segment of rod of length . By symmetry, the electric field must point radially outward, so outside of the rod, Gauss' law gives
Inside the rod, no charge is enclosed, so the flux through a concentric cylindrical Gaussian surface of radius is zero, and therefore the electric field inside the rod is zero.
Sphere with hole. A hollow charged sphere of radius and surface charge density contains a small circular hole of radius . What is the electric field right inside and outside of the hole?
Arbitrarily close to the hole, the hole essentially looks like a missing infinite plane. Thus, we can consider the electric field as resulting from the superposition of an infinite plane of charge density and a charged sphere of charge density .
Right outside of the hole, the field due to the plane is inward while the field due to the sphere is outward, so the net field is outward.
Right inside the hole, the field due to the plane is outward while the field due to the sphere is zero, so the net field is again outward.
We have a triangular uniformly charged plate of charge density .
We take a point just above a vertex of the triangular plate at a distance perpendicular to the plane of the triangle. Let the vertical component of electric field at that point be in
Details and Assumptions:
2) The triangle is equilateral. By vertical component of electric field I mean electric field perpendicular to the plane of charge.
3) The plate is non conducting.
The following examples illustrate how to calculate the capacitance of some of the most frequently encountered systems.
Parallel-plate capacitor. Two parallel identical conducting plates, each of area , are separated by a distance . Determine the capacitance of the plates.
Let the plates be aligned with the plane, and suppose the bottom plate holds charge while the other holds charge . The field between the plates is the sum of the contribution from each plate (which point in the same direction between the plates), which we know to be upward. Integrating over the separation distance gives
It follows that
Note that the field in the region outside of the plates is zero.
Capacitance of a spherical capacitor. Determine the capacitance of a conducting sphere of radius .
Using Gauss' law, it is easy to show that the electric field from a charged sphere is identical to that of a point source outside of the sphere. In other words, at a distance from the center of the sphere,
where is the net charge of the sphere. A single-sphere capacitor is essentially a double-sphere concentric capacitor with the outer sphere held at infinity. (Equivalently, one can simply consider the potential far away to be infinite.) Integrating gives
Coaxial cable. Determine the capacitance of a (cylindrical) coaxial cable of inner radius and outer radius . Suppose the cable is of length .
As we previously found, the field for is given simply by
where . Thus