Can you use the digits 1, 2, 3 4 and 5 (in some order), along with common mathematical operations, to make 2017?

Allowed:

Concatenation of digits
Addition, subtraction, multiplication, division
Fractions

Exponents, roots

Factorials

What about just the digits 1, 2, 3 and 4? Is that enough to reach 2017?

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## Comments

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TopNewest\(\frac{(4+3)!}{\frac{5}{2}}+1=\boxed{2017}\)

The other case seems quite difficult; given that 2017 is a prime number.

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found more by slightly modifying your solution-

\(\dfrac{((3!)+2)!}{5 \times 4}+1\),\(\dfrac{(3!)\times(4\times2)!}{5!}+1!\)

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Very similar to what I did, using 2016+1 :)

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Works fine :)

Any ideas about the 1,2,3,4 case?

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