1, 2, 3, 4, 5 = 2017

Can you use the digits 1, 2, 3 4 and 5 (in some order), along with common mathematical operations, to make 2017?

Allowed:
Concatenation of digits Addition, subtraction, multiplication, division Fractions
Exponents, roots
Factorials


What about just the digits 1, 2, 3 and 4? Is that enough to reach 2017?

Note by Chung Kevin
2 years, 8 months ago

No vote yet
1 vote

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(4+3)!52+1=2017\frac{(4+3)!}{\frac{5}{2}}+1=\boxed{2017}

The other case seems quite difficult; given that 2017 is a prime number.

Yatin Khanna - 2 years, 8 months ago

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found more by slightly modifying your solution-

((3!)+2)!5×4+1\dfrac{((3!)+2)!}{5 \times 4}+1,(3!)×(4×2)!5!+1!\dfrac{(3!)\times(4\times2)!}{5!}+1!

Anirudh Sreekumar - 2 years, 8 months ago

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Very similar to what I did, using 2016+1 :)

Chung Kevin - 2 years, 8 months ago

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@Chung Kevin 2017, being a prime it is hard!.I've gotten to 2016 so many times like- 2016= 25(431)2^5(4^3-1)

Anirudh Sreekumar - 2 years, 8 months ago

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@Anirudh Sreekumar Wow! Can you add all the different ways that you found?

Chung Kevin - 2 years, 8 months ago

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@Chung Kevin hey i got one more for 2017,(5!+3!)×42+1(5!+3!)\times 4^{2}+1

Anirudh Sreekumar - 2 years, 8 months ago

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Works fine :)
Any ideas about the 1,2,3,4 case?

Yatin Khanna - 2 years, 8 months ago

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@Yatin Khanna nope still trying :)

Anirudh Sreekumar - 2 years, 8 months ago

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