1, 2, 3, 4, 5 = 2017

Can you use the digits 1, 2, 3 4 and 5 (in some order), along with common mathematical operations, to make 2017?

Allowed:
Concatenation of digits Addition, subtraction, multiplication, division Fractions
Exponents, roots
Factorials

What about just the digits 1, 2, 3 and 4? Is that enough to reach 2017?

Note by Chung Kevin
4 years, 5 months ago

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$\frac{(4+3)!}{\frac{5}{2}}+1=\boxed{2017}$

The other case seems quite difficult; given that 2017 is a prime number.

- 4 years, 5 months ago

found more by slightly modifying your solution-

$\dfrac{((3!)+2)!}{5 \times 4}+1$,$\dfrac{(3!)\times(4\times2)!}{5!}+1!$

- 4 years, 5 months ago

Very similar to what I did, using 2016+1 :)

- 4 years, 5 months ago

2017, being a prime it is hard!.I've gotten to 2016 so many times like- 2016= $2^5(4^3-1)$

- 4 years, 5 months ago

Wow! Can you add all the different ways that you found?

- 4 years, 5 months ago

hey i got one more for 2017,$(5!+3!)\times 4^{2}+1$

- 4 years, 5 months ago

Works fine :)
Any ideas about the 1,2,3,4 case?

- 4 years, 5 months ago

nope still trying :)

- 4 years, 5 months ago