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# 1, 2, 3, 4, 5 = 2017

Can you use the digits 1, 2, 3 4 and 5 (in some order), along with common mathematical operations, to make 2017?

Allowed:
Concatenation of digits Addition, subtraction, multiplication, division Fractions
Exponents, roots
Factorials

What about just the digits 1, 2, 3 and 4? Is that enough to reach 2017?

Note by Chung Kevin
7 months ago

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$$\frac{(4+3)!}{\frac{5}{2}}+1=\boxed{2017}$$

The other case seems quite difficult; given that 2017 is a prime number. · 6 months, 4 weeks ago

found more by slightly modifying your solution-

$$\dfrac{((3!)+2)!}{5 \times 4}+1$$,$$\dfrac{(3!)\times(4\times2)!}{5!}+1!$$ · 6 months, 4 weeks ago

Very similar to what I did, using 2016+1 :) · 6 months, 4 weeks ago

2017, being a prime it is hard!.I've gotten to 2016 so many times like- 2016= $$2^5(4^3-1)$$ · 6 months, 4 weeks ago

Wow! Can you add all the different ways that you found? · 6 months, 4 weeks ago

hey i got one more for 2017,$$(5!+3!)\times 4^{2}+1$$ · 6 months, 4 weeks ago

Works fine :)
Any ideas about the 1,2,3,4 case? · 6 months, 4 weeks ago