1, 2, 3, 4, 5 = 2017

Can you use the digits 1, 2, 3 4 and 5 (in some order), along with common mathematical operations, to make 2017?

Allowed:
Concatenation of digits Addition, subtraction, multiplication, division Fractions
Exponents, roots
Factorials


What about just the digits 1, 2, 3 and 4? Is that enough to reach 2017?

Note by Chung Kevin
2 years, 4 months ago

No vote yet
1 vote

</code>...<code></code> ... <code>.">   Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in </span>...<span></span> ... <span> or </span>...<span></span> ... <span> to ensure proper formatting.
2 \times 3 2×3 2 \times 3
2^{34} 234 2^{34}
a_{i-1} ai1 a_{i-1}
\frac{2}{3} 23 \frac{2}{3}
\sqrt{2} 2 \sqrt{2}
\sum_{i=1}^3 i=13 \sum_{i=1}^3
\sin \theta sinθ \sin \theta
\boxed{123} 123 \boxed{123}

Comments

Sort by:

Top Newest

(4+3)!52+1=2017\frac{(4+3)!}{\frac{5}{2}}+1=\boxed{2017}

The other case seems quite difficult; given that 2017 is a prime number.

Yatin Khanna - 2 years, 4 months ago

Log in to reply

found more by slightly modifying your solution-

((3!)+2)!5×4+1\dfrac{((3!)+2)!}{5 \times 4}+1,(3!)×(4×2)!5!+1!\dfrac{(3!)\times(4\times2)!}{5!}+1!

Anirudh Sreekumar - 2 years, 4 months ago

Log in to reply

Very similar to what I did, using 2016+1 :)

Chung Kevin - 2 years, 4 months ago

Log in to reply

@Chung Kevin 2017, being a prime it is hard!.I've gotten to 2016 so many times like- 2016= 25(431)2^5(4^3-1)

Anirudh Sreekumar - 2 years, 4 months ago

Log in to reply

@Anirudh Sreekumar Wow! Can you add all the different ways that you found?

Chung Kevin - 2 years, 4 months ago

Log in to reply

@Chung Kevin hey i got one more for 2017,(5!+3!)×42+1(5!+3!)\times 4^{2}+1

Anirudh Sreekumar - 2 years, 4 months ago

Log in to reply

Works fine :)
Any ideas about the 1,2,3,4 case?

Yatin Khanna - 2 years, 4 months ago

Log in to reply

@Yatin Khanna nope still trying :)

Anirudh Sreekumar - 2 years, 4 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...