Can you use the digits 1, 2, 3 4 and 5 (in some order), along with common mathematical operations, to make 2017?

Allowed:

Concatenation of digits
Addition, subtraction, multiplication, division
Fractions

Exponents, roots

Factorials

What about just the digits 1, 2, 3 and 4? Is that enough to reach 2017?

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## Comments

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TopNewest$\frac{(4+3)!}{\frac{5}{2}}+1=\boxed{2017}$

The other case seems quite difficult; given that 2017 is a prime number.

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found more by slightly modifying your solution-

$\dfrac{((3!)+2)!}{5 \times 4}+1$,$\dfrac{(3!)\times(4\times2)!}{5!}+1!$

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Very similar to what I did, using 2016+1 :)

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$2^5(4^3-1)$

2017, being a prime it is hard!.I've gotten to 2016 so many times like- 2016=Log in to reply

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$(5!+3!)\times 4^{2}+1$

hey i got one more for 2017,Log in to reply

Works fine :)

Any ideas about the 1,2,3,4 case?

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