Can you use the digits 1, 2, 3 4 and 5 (in some order), along with common mathematical operations, to make 2017?

Allowed:

Concatenation of digits
Addition, subtraction, multiplication, division
Fractions

Exponents, roots

Factorials

What about just the digits 1, 2, 3 and 4? Is that enough to reach 2017?

## Comments

Sort by:

TopNewest\(\frac{(4+3)!}{\frac{5}{2}}+1=\boxed{2017}\)

The other case seems quite difficult; given that 2017 is a prime number. – Yatin Khanna · 6 months, 4 weeks ago

Log in to reply

\(\dfrac{((3!)+2)!}{5 \times 4}+1\),\(\dfrac{(3!)\times(4\times2)!}{5!}+1!\) – Anirudh Sreekumar · 6 months, 4 weeks ago

Log in to reply

– Chung Kevin · 6 months, 4 weeks ago

Very similar to what I did, using 2016+1 :)Log in to reply

– Anirudh Sreekumar · 6 months, 4 weeks ago

2017, being a prime it is hard!.I've gotten to 2016 so many times like- 2016= \(2^5(4^3-1)\)Log in to reply

– Chung Kevin · 6 months, 4 weeks ago

Wow! Can you add all the different ways that you found?Log in to reply

– Anirudh Sreekumar · 6 months, 4 weeks ago

hey i got one more for 2017,\((5!+3!)\times 4^{2}+1\)Log in to reply

Any ideas about the 1,2,3,4 case? – Yatin Khanna · 6 months, 4 weeks ago

Log in to reply

– Anirudh Sreekumar · 6 months, 4 weeks ago

nope still trying :)Log in to reply