Find all positive real numbers \(a\), \(b\) and \(c\) that satisfy the conditions:

\[a+b+c=75 \\ abc=2013 \\ a\leq3 \\ c\geq61\]

Give proof. You can write all families of positive real solutions.

Note that \(a,b\) and \(c\) might not necessarily be integers.

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## Comments

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TopNewestSince \(a\le 3\), \(b+c\le 72\) Similarly \(a+b\ge 14\).From this we get, \(14-a\le b\le 72-c\) again since \(a\le 3\) and \(c \ge 61\) we get \(11 \le b\le 11\) implies that \(b=11\). Now remains \(a+c=64\) and \(ac=183\) which on solving gives \(a=3,c=61\) @Sharky Kesa Please see if I am geting wrong:)

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Yup I have a pretty much same proof!

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a=3,b=11,c=61

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How do you know that is the only solution? How do you know there aren't any other

realsolutions? Where is your proof? You only wrote 1 integral solution.Log in to reply

@Sharky This can be proved to be the only real solution!

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