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A bead on a plane!

A bead of mass 'm' is placed on a smooth plane whose Cartesian equation is given by : ax+by+cz+d=0.

Given c is non-zero and a and b are not simultaneously zero, specify , by using a vector , the direction in which the bead rolls.

Note by Aditya Dhawan
1 month ago

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Well I thought the bead must roll along the planar projection of the weight {which I assumed to be along the negative z axis } , which is the vector given by subtracting the component of the weight along the normal vector (a,b,c) from the weight vector.

Aditya Dhawan - 1 month ago

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What have you tried?

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