Waste less time on Facebook — follow Brilliant.
×

A doubt

Please help me?

Note by A E
5 months, 3 weeks ago

No vote yet
1 vote

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

@A E Hi, I wanted an advice from your side.

I'm facing a problem regarding which books to refer, A Das Gupta or Cengage (As subjective might make me slow and objective might not ensure conceptual clarity). Could you kindly comment?

Swapnil Das - 1 month, 1 week ago

Log in to reply

i actually use cengage for both physics and maths. Cengage has quite a good number of subjective questions in each chapter,so you should not worry about conceptual clarity.

A E - 1 month, 1 week ago

Log in to reply

Thanks!

Swapnil Das - 1 month, 1 week ago

Log in to reply

Karthik Venkata - 1 month, 3 weeks ago

Log in to reply

Thanks!!!

A E - 1 month, 3 weeks ago

Log in to reply

Neat. I like this. I have to go now, but will come back and check this.

The way to approach this is to think equilibrium. If the thin rod is not moving, then it is in equilibrium. All torques (taken about any convenient point must sum to zero. And all forces must sum to zero.

Let mu the coefficient of friction be u... So imagine that u is large and the rod is horizontal. The CCW rotating axle gives the hoop a leftward pointing force. Take torques about the center of the hoop. That force is mu* m * g and it makes a torque out of the page equal to

r * u * m * g The bob makes a torque = m * g * (l+r) sine (theta) into the page and that is equal to the first torque.

So sine (theta) = r * u * m * g / ( m * g * ( l+r) ) = r * u / ( l+r)

Thus theta = arcsine ( r * u / ( l+r ) ) This is true for the hoop touching the axle at the top of the hoop.

it will touch at an angle though, and that will make the mg break into components, in the r * u * m * g part. So that is messier. I will come back to this.

Sandy Roman - 3 months ago

Log in to reply

Torque applies here??

Elethelectric Penguin - 3 months, 4 weeks ago

Log in to reply

Tan(Equlibruim angle)= (ur)/(l+r) Is that right ??

Ayush Sharma - 5 months ago

Log in to reply

Any ideas guyzzz????

A E - 5 months, 2 weeks ago

Log in to reply

Has anybody solved this yet?

A E - 5 months, 2 weeks ago

Log in to reply

Thanks for the q.let me try.

Spandan Senapati - 5 months, 2 weeks ago

Log in to reply

@Harsh Shrivastava

A E - 5 months, 2 weeks ago

Log in to reply

@Spandan Senapati

A E - 5 months, 2 weeks ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...