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TopNewest\( y = \frac {1} {2 - sin 3x} \) or \( y = \frac {1}{2} - sin 3x \) ? – Lokesh Sharma · 3 years, 8 months ago

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For second one, Range is \((-\frac{1}{2}, \frac{3}{2}) \) – Lokesh Sharma · 3 years, 8 months ago

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– Lokesh Sharma · 3 years, 8 months ago

Reason: The min and max value of \(sin x\) is \(-1\) and \(+1\) respectively.Log in to reply

– Priyansh Sangule · 3 years, 8 months ago

How do we find min. and max. values ?Log in to reply

– Akash Sinha · 3 years, 8 months ago

thanksLog in to reply

– Akash Sinha · 3 years, 8 months ago

1st oneLog in to reply