Waste less time on Facebook — follow Brilliant.
×

About functions

find range: y= 1/2-sin3x

Note by Akash Sinha
4 years, 1 month ago

No vote yet
1 vote

Comments

Sort by:

Top Newest

\( y = \frac {1} {2 - sin 3x} \) or \( y = \frac {1}{2} - sin 3x \) ?

Lokesh Sharma - 4 years, 1 month ago

Log in to reply

Anyway, for the first one, Range is \( (\frac {1}{3}, 1) \)

For second one, Range is \((-\frac{1}{2}, \frac{3}{2}) \)

Lokesh Sharma - 4 years, 1 month ago

Log in to reply

Reason: The min and max value of \(sin x\) is \(-1\) and \(+1\) respectively.

Lokesh Sharma - 4 years, 1 month ago

Log in to reply

@Lokesh Sharma How do we find min. and max. values ?

Priyansh Sangule - 4 years, 1 month ago

Log in to reply

thanks

Akash Sinha - 4 years, 1 month ago

Log in to reply

1st one

Akash Sinha - 4 years, 1 month ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...