# An equation to organize perfect squares in a sequence.

I have created an equation, I do not know if it has been made before. It organizes all of the perfect squares into a sequence.

$$s_{n}=((sqrt(s_{n-1})*2)+1)+s_{n-1}$$ Please note, I made this as a result of boredom. This is my first time posting a note or equation, do not mind the formatting errors. $$s_{1}=1$$

Note by Ethan Molin
3 years, 6 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

Interesting, I must have input the equation incorrectly. Thank you for notifying me of this.

- 3 years, 6 months ago

Are you sure the equation is correct? I'm getting $$s_3 = 13$$.

- 3 years, 6 months ago

I have corrected the error, thank you for informing me of this.

- 3 years, 6 months ago

Essentially, $$\displaystyle (a+1)^2=(a^2+2a+1)$$.

- 3 years, 6 months ago

Yes, but I was purposefully attempting to complete this without exponents.

- 3 years, 6 months ago