# An Interesting problem

Find the number of Integer solutions of this equation

x^8-y^36=10^100

Note by Subharthi Chowdhuri
4 years, 12 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

Well, its a guess. So please correct me if I'm wrong.
$(y^9)^4+(10^{25})^4=(x^2)^4$ This is in $$u^n+v^n=w^n$$ form. According to Fermat's last theorem, if n>2 then equation has no integral solution i.e. u,v,n can't be integers simultaneously. The question is in similar form so similar argument can be applied to the question too and it can be said that their is no integral solution of the question.

- 4 years, 12 months ago

absolutely correct. This is the correct explanation.

- 4 years, 12 months ago

no , it cannot be 101^2 , many of those out of them wont yield integer values of x and y

- 4 years, 12 months ago

Is the answer $$101^2$$?

- 4 years, 12 months ago