Area of a triangle = \(\large \dfrac 4 3 * \) (area of triangle formed by the three medians.)

If u,v,w are the lengths of the medians, the area is also =\(\large \dfrac{ 1}{ 3} *\sqrt{2(u^2v^2+v^2w^2+w^2u^2) -(u^4+v^4+w^4)}.\)

If u,v,w are the lengths of the medians, the area is also =\(\large \dfrac{ 1}{ 3} *\sqrt{2(u^2v^2+v^2w^2+w^2u^2) -(u^4+v^4+w^4)}.\)

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TopNewestsir maybe you could just go to the site of University of Georgia and then look for this page on area of triangle given median lengths or you could just Google the above topic and I believe there is another webpage on the same topic which is very informative and there are other forms of the formula as well. thank you – Sathvik Acharya · 2 months ago

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– Niranjan Khanderia · 2 months ago

Thank you.Log in to reply

http://jwilson.coe.uga.edu/emt725/Medians.Triangle/Area.Medians.Tri.html. That's for extra information, I found it wonderful – Sathvik Acharya · 2 months ago

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I was not allowed ! Any other way to see what you suggest ? Thanks. – Niranjan Khanderia · 2 months ago

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Cannot understand what you nean by 4/3 – Aman Real · 2 years, 1 month ago

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– Niranjan Khanderia · 1 year, 12 months ago

One and one third.Log in to reply