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# Base divisibility

Prove or disprove (I think it's true, but I don't have pencil nor paper so I can't work on this at the moment) that if

$$\dfrac{a_c}{b_c}=x_c$$

Where a,b,c,x are integers and c does not divide x without remainder; then

$$\dfrac{a_{10}}{b_{10}}=x_{10}$$

Assume:

$$a_c$$ means a in base c.

Note by Trevor Arashiro
1 year, 9 months ago