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prove that the number 100020001 has a natural root.??

Note by Mobin Moradi
1 year, 9 months ago

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We'll be using the following identity - \[x^2+2x+1=(x+1)^2\]

Now, observe that

\[100020001 = 10^8+2\times10^4+1 = (10^4)^2+2(10^4)+1 = (10^4+1)^2\]

Thus,

\[\sqrt{100020001} = 10001\] Kishlaya Jaiswal · 1 year, 9 months ago

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